Nitrating aniline
"Nitrating aniline" is a free, interactive Class 12 Chemistry simulation for NEET and JEE, built on the NCERT section "Electrophilic substitution in aniline" in Amines. Aniline in nitrating acid: a slider for how much is protonated to meta-directing anilinium shifts the product split towards 51% p / 47% m / 2% o; protecting as acetanilide restores para; AlCl₃ shows the Friedel-Crafts dead end. NEET has asked about this idea 2 times in 10 years of papers. JEE Main asked 57 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Electrophilic substitution in aniline in Amines. Change the values and watch what happens.
What it shows
NCERT §9.6
Aniline in nitrating acid: a slider for how much is protonated to meta-directing anilinium shifts the product split towards 51% p / 47% m / 2% o; protecting as acetanilide restores para; AlCl₃ shows the Friedel-Crafts dead end.
Controls
4 to try
- Sliderfraction protonated 0–1
- Togglefree –NH₂ / acetanilide protected
- Togglereagent HNO₃/H₂SO₄ / Br₂ water / R–Cl + AlCl₃
- Readoutso/m/p %, ring activated or deactivated
Try this
Get p-nitroaniline above 90% of the product.
Common mistake
Direct nitration of aniline gives only ortho/para products.
In NEET
10 years of papers
Asked 2 times in 10 years of NEET.
See the past questions: Amines and Diazonium Salts, Amines (chapter)
In JEE Main
42 shifts analysed
57 questions from Amines across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §9.6
- The resonance structures of aniline pile electron density onto the ortho and para positions, so –NH₂ is a powerful activating, ortho- and para-directing group.
- Bromination: aniline and bromine water at room temperature give a white precipitate of 2,4,6-tribromoaniline at once.
- To stop at one substituent, –NH₂ is protected by acetylation with acetic anhydride (pyridine), the substitution is done on acetanilide, and the amide is then hydrolysed back to the amine. Acetanilide with Br₂ in CH₃COOH gives mainly the para product, and hydrolysis gives 4-bromoaniline.
- In acetanilide the nitrogen lone pair is also shared with the carbonyl oxygen by resonance, so it is less available to the ring and –NHCOCH₃ activates less than –NH₂.
- Nitration: direct nitration (HNO₃, H₂SO₄, 288 K) gives tarry oxidation products as well as nitroanilines. In strong acid much of the aniline becomes the anilinium ion, which is meta-directing, so the product mix is 51% para, 47% meta and 2% ortho.
- Nitrating acetanilide instead, then hydrolysing, gives p-nitroaniline as the main product.
- Sulphonation: aniline with concentrated H₂SO₄ forms anilinium hydrogensulphate, which on heating at 453–473 K gives p-aminobenzenesulphonic acid (sulphanilic acid) as the main product; it exists as a zwitter ion.
- Aniline gives no Friedel-Crafts reaction: it forms a salt with the AlCl₃ catalyst, and the positively charged nitrogen then strongly deactivates the ring.
Questions
5 answers
- What does the "Nitrating aniline" simulation show?
- Aniline in nitrating acid: a slider for how much is protonated to meta-directing anilinium shifts the product split towards 51% p / 47% m / 2% o; protecting as acetanilide restores para; AlCl₃ shows the Friedel-Crafts dead end.
- What mistake does the "Nitrating aniline" simulation fix?
- A common mistake it clears up: direct nitration of aniline gives only ortho/para products.
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 2 times in 10 years of papers.
- Does JEE Main ask questions from Amines?
- Yes. JEE Main asked 57 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Electrophilic substitution in aniline" in Amines (Class 12 Chemistry).
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