Why does a little heat speed a reaction so much?
"Why does a little heat speed a reaction so much?" is a free, interactive Class 12 Chemistry simulation for NEET and JEE, built on the lesson "Temperature and the Arrhenius equation" in Chemical Kinetics. The top graph is the Arrhenius plot: ln k against 1/T, a straight line of slope −Ea/R. The lower graph shows the fraction of molecules with at least a given energy, on a log scale, at T (solid) and 10 K hotter (dashed). A is held at 10¹⁰ s⁻¹ here. K = A e^(−Ea/RT). Only the molecules with energy ≥ Ea react, a fraction e^(−Ea/RT) that is tiny but very sensitive to T. Plot ln k against 1/T: the slope is −Ea/R, and a larger Ea means a steeper line and a stronger response to heat. JEE Main asked 48 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Temperature and the Arrhenius equation in Chemical Kinetics. Change the values and watch what happens.
In JEE Main
42 shifts analysed
48 questions from Chemical Kinetics across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §3.4
- Most reactions speed up with temperature. N₂O₅ in the gas phase has a half-life of about 12 min at 50 °C, 5 h at 25 °C and 10 days at 0 °C. A mixture of KMnO₄ and oxalic acid decolourises faster when warm.
- For many reactions a rise of 10 °C roughly doubles the rate constant.
- Arrhenius equation: k = A e^(−Ea/RT). A is the Arrhenius (frequency) factor, Ea the activation energy in J mol⁻¹ and R = 8.314 J K⁻¹ mol⁻¹.
- Reactants must pass through a short-lived, high-energy activated complex before becoming products. For H₂ + I₂ → 2HI the complex has partly broken H–H and I–I bonds and partly formed H–I bonds. Ea is the energy needed to reach it from the reactants.
- At a given temperature molecules have a spread of kinetic energies (the Maxwell-Boltzmann distribution). The peak is at the most probable energy. A higher temperature flattens the curve and shifts the peak to higher energy; the total area stays the same because the number of molecules is fixed.
- e^(−Ea/RT) is the fraction of molecules with energy at least Ea. Raising T by 10 °C nearly doubles the area beyond Ea, which is why rate nearly doubles.
- Taking logs: ln k = ln A − Ea/RT. A plot of ln k against 1/T is a straight line with slope −Ea/R and intercept ln A.
- Two temperatures: log(k₂/k₁) = [Ea/(2.303R)] × [(T₂ − T₁)/(T₁T₂)]. For k = 0.02 s⁻¹ at 500 K and 0.07 s⁻¹ at 700 K, this gives Ea = 18.2 kJ mol⁻¹.
- If k doubles between 298 K and 308 K, Ea = 2.303R × log 2 × (298 × 308)/10 = 52.9 kJ mol⁻¹.
Questions
3 answers
- What does the "Why does a little heat speed a reaction so much?" simulation show?
- The top graph is the Arrhenius plot: ln k against 1/T, a straight line of slope −Ea/R. The lower graph shows the fraction of molecules with at least a given energy, on a log scale, at T (solid) and 10 K hotter (dashed). A is held at 10¹⁰ s⁻¹ here.
- Does JEE Main ask questions from Chemical Kinetics?
- Yes. JEE Main asked 48 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Temperature and the Arrhenius equation" in Chemical Kinetics (Class 12 Chemistry).
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