How does the ligand set the colour of a complex?
"How does the ligand set the colour of a complex?" is a free, interactive Class 12 Chemistry simulation for NEET and JEE, built on the NCERT section "Colour in coordination compounds" in Coordination Compounds. Slide a ligand along the spectrochemical series for one metal ion: Δo grows, the absorbed wavelength shortens (λ = hc/Δo) and the colour seen is the complement on a colour wheel. NEET has asked about this idea 5 times in 10 years of papers. JEE Main asked 80 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Colour in coordination compounds in Coordination Compounds. Change the values and watch what happens.
What it shows
NCERT §5.5.4; §5.5.5
Slide a ligand along the spectrochemical series for one metal ion: Δo grows, the absorbed wavelength shortens (λ = hc/Δo) and the colour seen is the complement on a colour wheel.
Controls
3 to try
- Sliderligand I⁻ … Cl⁻ … H₂O … NH₃ … en … CN⁻ … CO
- Togglemetal Co³⁺ / Ti³⁺ / Ni²⁺
- ReadoutsΔo (kJ mol⁻¹), absorbed λ (nm), absorbed colour, colour seen
Try this
Pick the ligand that makes the cobalt(III) complex absorb near 475 nm and name the colour it looks (yellow-orange)
Common mistake
Reporting the absorbed colour as the colour seen / charged ligands always split most.
In NEET
10 years of papers
Asked 5 times in 10 years of NEET.
See the past questions: Crystal Field Theory, Coordination Compounds (chapter)
In JEE Main
42 shifts analysed
80 questions from Coordination Compounds across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §5.5.5; §5.5.6
- A coloured complex absorbs part of the visible light passing through it; its colour is the complementary colour of what is left. If green is absorbed, the complex looks red.
- Absorbed wavelength and colour seen: [CoCl(NH₃)₅]²⁺ 535 nm (yellow) looks violet; [Co(NH₃)₅(H₂O)]³⁺ 500 nm (blue-green) looks red; [Co(NH₃)₆]³⁺ 475 nm (blue) looks yellow-orange.
- More pairs: [Co(CN)₆]³⁻ absorbs at 310 nm in the ultraviolet and is pale yellow; [Cu(H₂O)₄]²⁺ absorbs 600 nm (red) and looks blue; [Ti(H₂O)₆]³⁺ absorbs 498 nm (blue-green) and looks violet.
- [Ti(H₂O)₆]³⁺ is d¹: the lone electron sits in t₂g. Blue-green light promotes it to eg (t₂g¹eg⁰ → t₂g⁰eg¹), so the complex looks violet. CFT puts colour down to such d-d transitions.
- No ligand, no splitting, no colour: heating [Ti(H₂O)₆]Cl₃ to drive off water leaves a colourless solid, and anhydrous CuSO₄ is white while CuSO₄·5H₂O is blue.
- Changing the ligand changes the colour. Adding en to green [Ni(H₂O)₆]²⁺ in en:Ni ratios 1:1, 2:1 and 3:1 gives pale blue [Ni(H₂O)₄(en)]²⁺, blue/purple [Ni(H₂O)₂(en)₂]²⁺ and violet [Ni(en)₃]²⁺.
- Ruby is Al₂O₃ with about 0.5-1% Cr³⁺ (d³) in some Al³⁺ sites; these act like octahedral Cr(III) complexes whose d-d transitions give the colour. In emerald, Cr³⁺ sits in octahedral sites of beryl (Be₃Al₂Si₆O₁₈); its bands move to longer wavelengths (yellow-red and blue), so green is transmitted.
- Limits of CFT: treating ligands as point charges predicts that anions should split most, yet anionic ligands sit at the weak end of the spectrochemical series; and CFT ignores the covalent side of metal-ligand bonding. Ligand field and molecular orbital theories handle these.
Questions
5 answers
- What does the "How does the ligand set the colour of a complex?" simulation show?
- Slide a ligand along the spectrochemical series for one metal ion: Δo grows, the absorbed wavelength shortens (λ = hc/Δo) and the colour seen is the complement on a colour wheel.
- What mistake does the "How does the ligand set the colour of a complex?" simulation fix?
- A common mistake it clears up: reporting the absorbed colour as the colour seen / charged ligands always split most.
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 5 times in 10 years of papers.
- Does JEE Main ask questions from Coordination Compounds?
- Yes. JEE Main asked 80 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Colour in coordination compounds" in Coordination Compounds (Class 12 Chemistry).
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