Hydrocarbons

Chemistry · Class 11

Simulation · Chemistry · Class 11

Ozonolysis: cut the C=C

"Ozonolysis: cut the C=C" is a free, interactive Class 11 Chemistry simulation for NEET and JEE, built on the NCERT section "Properties and reactions of alkenes" in Hydrocarbons. Build an alkene from substituents on each sp² carbon; ozonolysis cuts the C=C into two carbonyl fragments, and reverse mode joins given carbonyls back into the parent alkene. NEET has asked about this idea 3 times in 10 years of papers. JEE Main asked 34 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).

From the lesson Properties and reactions of alkenes in Hydrocarbons. Change the values and watch what happens.

Ozonolysis: cut the C=CChemistry · Class 11

What it shows

NCERT §9.3.5

Build an alkene from substituents on each sp² carbon; ozonolysis cuts the C=C into two carbonyl fragments, and reverse mode joins given carbonyls back into the parent alkene.

Controls

3 to try

  • Segmentedtwo substituents on C1 (H / CH3 / C2H5 / Ph)
  • Segmentedtwo substituents on C2
  • Toggleforward (cut) / reverse (join)

Try this

Reverse mode: given one ethanal and one propanone, assemble the parent alkene (2-methylbut-2-ene); goal checks the substituent sets.

Common mistake

Placing the cut at a C–C single bond; reversing to the wrong isomer.

In NEET

10 years of papers

Asked 3 times in 10 years of NEET.

See the past questions: Hydrocarbons (Alkenes), Hydrocarbons (chapter)

In JEE Main

42 shifts analysed

34 questions from Hydrocarbons across the 42 JEE Main shifts Lumi has analysed (2017–2026).

See the past questions

The idea behind it

NCERT §9.3.5

  • Alkenes C₂ to C₄ are gases, then fourteen members are liquids, and higher ones are solid. Ethene has a faintly sweet smell; other alkenes have none. None of them dissolves in water, but all dissolve fairly well in non-polar solvents such as benzene and petroleum ether. Each added CH₂ raises the boiling point by 20–30 K.
  • Bromine or chlorine adds to give a vicinal dihalide (through a cyclic halonium ion); iodine does not add under normal conditions. Loss of the reddish orange colour of bromine in CCl₄ is a test for unsaturation.
  • Hydrogen halides add to give alkyl halides, with reactivity HI > HBr > HCl. A symmetrical alkene gives one product: ethene + HBr gives bromoethane.
  • Markovnikov rule (1869): when an unsymmetrical reagent adds to an unsymmetrical alkene, its negative part joins the double-bond carbon that carries fewer hydrogens. Propene + HBr gives mainly 2-bromopropane.
  • Mechanism: H⁺ attacks first, forming the more stable carbocation (secondary rather than primary), which forms faster; Br⁻ then bonds to that positive carbon.
  • Peroxide (Kharash) effect: with benzoyl peroxide, HBr adds to propene against Markovnikov's rule, giving 1-bromopropane, by a free-radical chain through the more stable secondary radical. Hex-1-ene gives 2-bromohexane without peroxide and 1-bromohexane with it.
  • Only HBr shows the peroxide effect. H–Cl (430.5 kJ mol⁻¹) is too strong for the radical to break, and I• radicals join to form I₂ rather than add, even though H–I (296.8 kJ mol⁻¹) is weaker than H–Br (363.7 kJ mol⁻¹).
  • Cold concentrated H₂SO₄ adds by Markovnikov's rule to give alkyl hydrogen sulphates; water with a few drops of concentrated H₂SO₄ adds by the same rule to give alcohols.
  • Cold dilute aqueous KMnO₄ (Baeyer's reagent) turns alkenes into vicinal glycols, and its loss of colour is a test for unsaturation. Acidic KMnO₄ or K₂Cr₂O₇ cleaves them to ketones and/or acids; but-2-ene gives two molecules of ethanoic acid.
  • Ozonolysis adds O₃ to form an ozonide, which Zn–H₂O splits into smaller carbonyl compounds; the fragments reveal where the double bond was. Polymerisation at high temperature and pressure with a catalyst turns ethene into polythene and propene into polypropene.

Questions

5 answers

What does the "Ozonolysis: cut the C=C" simulation show?
Build an alkene from substituents on each sp² carbon; ozonolysis cuts the C=C into two carbonyl fragments, and reverse mode joins given carbonyls back into the parent alkene.
What mistake does the "Ozonolysis: cut the C=C" simulation fix?
A common mistake it clears up: placing the cut at a C–C single bond; reversing to the wrong isomer.
Has NEET asked about this idea?
Yes. NEET has asked about this idea 3 times in 10 years of papers.
Does JEE Main ask questions from Hydrocarbons?
Yes. JEE Main asked 34 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
Is this simulation free?
Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Properties and reactions of alkenes" in Hydrocarbons (Class 11 Chemistry).

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