Why 4s fills before 3d
"Why 4s fills before 3d" is a free, interactive Class 11 Chemistry simulation for NEET and JEE, built on the NCERT section "Shapes and energies of orbitals" in Structure of Atom. Orbital energy levels for hydrogen (all subshells of a shell degenerate) morph into a multi-electron atom where s<p<d<f split and 4s drops below 3d by the (n + l) rule. NEET has asked about this idea 3 times in 10 years of papers. JEE Main asked 46 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Shapes and energies of orbitals in Structure of Atom. Change the values and watch what happens.
What it shows
NCERT §2.6.2; §2.6.3
Orbital energy levels for hydrogen (all subshells of a shell degenerate) morph into a multi-electron atom where s<p<d<f split and 4s drops below 3d by the (n + l) rule.
Controls
3 to try
- Toggleone-electron atom / many-electron atom
- Slidershielding strength 0–1 (morphs between the two)
- Tapany two orbitals to compare n + l
Try this
In the many-electron view, order 3d, 4s and 4p correctly by tapping the lowest first; then switch to hydrogen and find a pair that becomes degenerate (e.g. 3s and 3d).
Common mistake
3d fills before 4s because 3 < 4; in hydrogen 2s is lower than 2p.
In NEET
10 years of papers
Asked 3 times in 10 years of NEET.
See the past questions: Quantum Numbers, Structure of Atom (chapter)
In JEE Main
42 shifts analysed
46 questions from Structure of Atom across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §2.6.2; §2.6.3
- For 1s, |ψ|² is highest at the nucleus and falls away steadily; for 2s it falls to zero, rises to a small maximum and falls again. A surface where the probability density is zero is a node.
- A boundary surface diagram encloses the region with about 90% probability; 100% is impossible because |ψ|² never becomes exactly zero at any finite distance. Every s orbital is a sphere, and size grows 1s < 2s < 3s < 4s.
- Each p orbital has two lobes on either side of a nodal plane through the nucleus; the three (px, py, pz) are equal in size, shape and energy and lie along mutually perpendicular axes. There is no simple match between mₗ values and x, y, z.
- The five d orbitals (from n = 3 onwards) are dxy, dyz, dxz, dx²−y² and dz²; the first four share a shape, dz² looks different, and all five are equal in energy in the isolated atom.
- Nodes: angular nodes = l, radial nodes = n − l − 1, total = n − 1. So 2s has one radial node, 3p has one radial and one angular, and pz has the xy-plane as its nodal plane.
- In hydrogen, energy depends on n alone, so all subshells of one shell tie: 2s = 2p; 3s = 3p = 3d; and 4s, 4p, 4d and 4f are equal too. Orbitals of equal energy are called degenerate.
- In multi-electron atoms, electron-electron repulsion and shielding make energy depend on n and l: within a shell s < p < d < f, because an s electron penetrates closer to the nucleus and feels a larger effective nuclear charge (Zeff).
- The (n + l) rule: lower n + l means lower energy; for equal n + l, lower n is lower. This gives 4s < 3d, 6s < 5d and 4f < 6p. The same orbital drops in energy as Z rises: E₂ₛ(H) > E₂ₛ(Li) > E₂ₛ(Na) > E₂ₛ(K).
Questions
5 answers
- What does the "Why 4s fills before 3d" simulation show?
- Orbital energy levels for hydrogen (all subshells of a shell degenerate) morph into a multi-electron atom where s<p<d<f split and 4s drops below 3d by the (n + l) rule.
- What mistake does the "Why 4s fills before 3d" simulation fix?
- A common mistake it clears up: 3d fills before 4s because 3 < 4; in hydrogen 2s is lower than 2p.
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 3 times in 10 years of papers.
- Does JEE Main ask questions from Structure of Atom?
- Yes. JEE Main asked 46 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Shapes and energies of orbitals" in Structure of Atom (Class 11 Chemistry).
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