Terminal velocity: when the forces balance
"Terminal velocity: when the forces balance" is a free, interactive Class 11 Physics simulation for NEET and JEE, built on the NCERT section "Viscosity and Stokes' law" in Mechanical Properties of Fluids. A sphere falls through a liquid; weight, buoyancy and 6πηav drag bars; v-t curve levels to v_t = 2a²(ρ−σ)g/9η. NEET has asked about this idea 4 times in 10 years of papers. JEE Main asked 39 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Viscosity and Stokes' law in Mechanical Properties of Fluids. Change the values and watch what happens.
What it shows
NCERT §9.5.1
A sphere falls through a liquid; weight, buoyancy and 6πηav drag bars; v-t curve levels to v_t = 2a²(ρ−σ)g/9η.
Controls
4 to try
- Slidersphere radius 0.5–5 mm
- Slidersphere density 1–11 g/cm³
- Togglefluid (water, glycerine, oil, honey)
- Toggleshow power dissipated
Try this
Choose the radius of a steel ball so it falls through glycerine at 5 cm/s; then double the radius and predict v_t.
Common mistake
Terminal velocity grows linearly with radius; viscous force alone balances weight (buoyancy forgotten).
In NEET
10 years of papers
Asked 4 times in 10 years of NEET.
See the past questions: Fluid Viscosity, Mechanical Properties of Fluids (chapter)
In JEE Main
42 shifts analysed
39 questions from Mechanical Properties of Fluids across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §9.5, §9.5.1
- Real fluids resist motion through a kind of internal friction between layers moving relative to one another. This is viscosity.
- Oil between two glass plates, lower plate fixed, upper plate moved at constant velocity v: honey in place of oil needs a bigger force for the same v, so honey is more viscous.
- The fluid touching a surface moves with that surface: the top layer at v, the bottom layer at rest, with speed rising uniformly between. Each layer is pulled forward by the one above and back by the one below; this is laminar flow, like pages of a book sliding when the cover is pushed.
- In a pipe the layer along the axis moves fastest and the speed falls to zero at the walls; the speed is constant over any cylindrical surface coaxial with the tube.
- A shape ABCD in the fluid becomes AEFD after a time Δt, a shear strain Δx/l that keeps growing. Unlike a solid, the stress depends on the strain rate Δx/(lΔt) = v/l, not on the strain itself.
- Coefficient of viscosity η = shearing stress ÷ strain rate = (F/A)/(v/l) = Fl/(vA). SI unit poiseuille (Pl), also N s m⁻² or Pa s; dimensions [ML⁻¹T⁻¹].
- Viscosities (mPl), thin liquids low and thick ones high; blood's viscosity relative to water stays constant from 0 °C to 37 °C: water 1.0 at 20 °C and 0.3 at 100 °C; blood 2.7 at 37 °C; machine oil 113 at 16 °C and 34 at 38 °C; glycerine 830 at 20 °C; honey 200; air 0.017 at 0 °C and 0.019 at 40 °C.
- The viscosity of a liquid falls as temperature rises (its molecules become more mobile); the viscosity of a gas rises (random motion increases).
- Block of area 0.10 m² on a 0.30 mm liquid film, pulled by a 0.010 kg hanging mass over an ideal pulley, slides at a steady 0.085 m s⁻¹: F = 9.8 × 10⁻² N, shear stress 0.98 N m⁻², strain rate 0.085/(0.30 × 10⁻³) s⁻¹, η = 3.46 × 10⁻³ Pa s.
- Stokes' law: a sphere of radius a moving at speed v through a fluid of viscosity η feels a drag F = 6πηav, opposite to its motion and proportional to its speed. Raindrops and swinging pendulum bobs meet this drag.
- A falling sphere speeds up until viscous drag plus buoyancy equals its weight; then it falls at a constant terminal velocity: 6πηa v_t = (4π/3)a³(ρ − σ)g, so v_t = 2a²(ρ − σ)g/(9η), with ρ the sphere's density and σ the fluid's. v_t grows as the square of the radius and falls inversely with the viscosity.
- Copper ball, radius 2.0 mm, falling through oil at 20 °C with terminal velocity 6.5 cm s⁻¹ (ρ = 8.9 × 10³, σ = 1.5 × 10³ kg m⁻³, g = 9.8 m s⁻²): η = 2a²(ρ − σ)g/(9v_t) = 9.9 × 10⁻¹ kg m⁻¹ s⁻¹.
Questions
5 answers
- What does the "Terminal velocity: when the forces balance" simulation show?
- A sphere falls through a liquid; weight, buoyancy and 6πηav drag bars; v-t curve levels to v_t = 2a²(ρ−σ)g/9η.
- What mistake does the "Terminal velocity: when the forces balance" simulation fix?
- A common mistake it clears up: terminal velocity grows linearly with radius; viscous force alone balances weight (buoyancy forgotten).
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 4 times in 10 years of papers.
- Does JEE Main ask questions from Mechanical Properties of Fluids?
- Yes. JEE Main asked 39 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Viscosity and Stokes' law" in Mechanical Properties of Fluids (Class 11 Physics).
Embed this simulation
Free, with a link back
Teaching this idea? Put the simulation on your own page or LMS with this code.