SHM as the shadow of a particle on a circle
"SHM as the shadow of a particle on a circle" is a free, interactive Class 11 Physics simulation for NEET and JEE, built on the NCERT section "SHM as the shadow of uniform circular motion" in Oscillations. A reference particle on a circle with its projection doing SHM; x, v and a graphs scroll together with π/2 and π phase gaps. NEET has asked about this idea 5 times in 10 years of papers. JEE Main asked 29 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson SHM as the shadow of uniform circular motion in Oscillations. Change the values and watch what happens.
What it shows
NCERT §13.4, §13.5
A reference particle on a circle with its projection doing SHM; x, v and a graphs scroll together with π/2 and π phase gaps.
Controls
4 to try
- Slideramplitude 1–10 cm
- Sliderω 0.5–5 rad/s
- Dragstarting angle φ
- Toggleclockwise / anticlockwise
Try this
Set φ so the particle starts at x = A/2 moving towards −x, and read the equation x = A cos(ωt + π/3).
Common mistake
Putting degrees into the phase; v and a in phase with x.
In NEET
10 years of papers
Asked 5 times in 10 years of NEET.
See the past questions: Simple Harmonic Motion, Oscillations (chapter)
In JEE Main
42 shifts analysed
29 questions from Oscillations across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §13.4
- If a particle P goes round a circle of radius A at a steady angular speed ω, its projection P′ on any diameter moves in simple harmonic motion.
- When OP makes an angle φ with the +x axis at t = 0 and turns anticlockwise, the angle at time t is ωt + φ and the projection is x(t) = A cos(ωt + φ): radius = amplitude, angular speed = angular frequency, starting angle = phase constant.
- P is called the reference particle and its circle the reference circle.
- A ball whirled in a horizontal circle, watched edge-on or through its shadow on a wall perpendicular to the plane of the circle, appears to move to and fro along a straight line centred on the point of rotation.
- The projection on the y-axis, y = A sin(ωt + φ), is also SHM of the same amplitude but differs in phase by π/2 from the x-projection.
- A clockwise sense makes the angle decrease with time. A point that starts at 90° and turns clockwise with period T has x-projection B cos(π/2 − 2πt/T) = B sin(2πt/T). With a 30 s period this becomes B cos(πt/15 − π/2): phase constant −π/2.
- Starting at 45° and turning anticlockwise with period 4 s, the x-projection is A cos(2πt/4 + π/4): amplitude A, period 4 s, phase constant π/4.
- The link is geometric only. The force on a body in linear SHM acts along the line, towards the mean point, and grows with displacement; the centripetal force that keeps P on its circle has a constant magnitude.
Questions
5 answers
- What does the "SHM as the shadow of a particle on a circle" simulation show?
- A reference particle on a circle with its projection doing SHM; x, v and a graphs scroll together with π/2 and π phase gaps.
- What mistake does the "SHM as the shadow of a particle on a circle" simulation fix?
- A common mistake it clears up: putting degrees into the phase; v and a in phase with x.
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 5 times in 10 years of papers.
- Does JEE Main ask questions from Oscillations?
- Yes. JEE Main asked 29 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "SHM as the shadow of uniform circular motion" in Oscillations (Class 11 Physics).
Embed this simulation
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