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Friday, 16 October

JEE Main 2020 · PhysicsNumerical answerNumerical valueMediumMulti-step

JEE Main 2 September 2020, Shift 1, Physics Q22

Question 22 of 75 in this shift, Physics question 22 of 25.

An engine takes in 5 moles of air at 20∘20^\circC and 1 atm, and compresses it adiabaticaly to 1/10th1/10^{\mathrm{th}} of the original volume. Assuming air to be a diatomic ideal gas made up of rigid molecules, the change in its internal energy during this process comes out to be XX kJ. The value of XX to the nearest integer is ______.

Official answer

46.00

NTA final key (Sep 2020).

Chapter
Thermodynamics
Topic
Thermodynamic Processes
Idea tested
Adiabatic T-V and P-T Relations

Same idea in other shifts

Asked 3× in all
  1. 25 Jul 2021, Shift 1 · Q20A monoatomic ideal gas, initially at temperature T1T_1 is enclosed in a cylinder fitted with a frictionless piston. The gas is allowed to…EasySingle correct
  2. 9 Jan 2020, Shift 2 · Q21Starting at temperature 300 K, one mole of an ideal diatomic gas (γ=1.4\gamma = 1.4) is first compressed adiabatically from volume V1V_1 to…MediumNumerical value

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.