JEE Main 2024 (9 Apr, Shift 1) Physics Q44: A plane EM…

Question

A plane EM wave is propagating along $x$ direction. It has a wavelength of $4$ mm. If electric field is in $y$ direction with the maximum magnitude of $60\ \mathrm{Vm^{-1}}$, the equation for magnetic field is :

Accepted Answer

Option 4: $B_z=2	imes10^{-7}\sin\left[\frac{\pi}{2}	imes10^3\left(x-3	imes10^8tight)ight]\hat{k}\ \mathrm{T}$

Answer

$B_z=60\sin\left[\frac{\pi}{2}\left(x-3	imes10^8tight)ight]\hat{k}\ \mathrm{T}$

Answer

$B_x=60\sin\left[\frac{\pi}{2}\left(x-3	imes10^8tight)ight]\hat{i}\ \mathrm{T}$

Answer

$B_z=2	imes10^{-7}\sin\left[\frac{\pi}{2}\left(x-3	imes10^8tight)ight]\hat{k}\ \mathrm{T}$

Answer

$B_z=2	imes10^{-7}\sin\left[\frac{\pi}{2}	imes10^3\left(x-3	imes10^8tight)ight]\hat{k}\ \mathrm{T}$

JEE Main 9 April 2024, Shift 1, Physics Q44