JEE Main 2025 · PhysicsMultiple choiceSingle correctEasyCalculation

JEE Main 3 April 2025, Shift 2, Physics Q37

Question 37 of 75 in this shift, Physics question 12 of 25, Section A.

An electric bulb rated as 100W-220V is connected to an ac source of rms voltage 220V. The peak value of current through the bulb is :

(1)0.45 A
(2)0.32 A
(3)0.64 AOfficial answer
(4)2.2 A

Official answer

Option 3

NTA final key.

Chapter: Alternating Current
Topic: RMS and Peak Values
Idea tested: Sinusoidal RMS-Peak Relation

Same topic in other shifts

All RMS and Peak Values questions

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24 Jun 2022, Shift 1 · Q41A resistance of $40\ \Omega$ is connected to a source of alternating current rated 220 V, 50 Hz. Find the time taken by the current to…EasySingle correct
18 Mar 2021, Shift 1 · Q6An AC source rated 220 V, 50 Hz is connected to a resistor. The time taken by the current to change from its maximum to the rms value is :EasySingle correct

Question text from the official JEE Main paper published by NTA; answer from the final answer key. Chapter, topic and idea tags, difficulty and skill are Lumi’s. Lumi analyses 42 of the 174 JEE Main shifts held from 2017 to 2026.