Heating limestone in a closed vessel
"Heating limestone in a closed vessel" is a free, interactive Class 11 Chemistry simulation for NEET and JEE, built on the NCERT section "Homogeneous and heterogeneous equilibria; Kp" in Equilibrium. CaCO3 heated in a closed vessel: the CO2 pressure settles to Kp whatever the amount of solid, and only temperature moves it; a side panel computes Kp/Kc = (RT)^Δn for chosen reactions. NEET has asked about this idea 2 times in 10 years of papers. JEE Main asked 52 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Homogeneous and heterogeneous equilibria; Kp in Equilibrium. Change the values and watch what happens.
What it shows
NCERT § "Homogeneous Equilibria"; § "Heterogeneous Equilibria"
CaCO3 heated in a closed vessel: the CO2 pressure settles to Kp whatever the amount of solid, and only temperature moves it; a side panel computes Kp/Kc = (RT)^Δn for chosen reactions.
Controls
3 to try
- SliderCaCO3 mass 1–100 g
- Slidertemperature 900–1200 K
- Segmentedreaction for Kp-Kc: H2+I2 / PCl5 / N2+3H2 / CaCO3
Try this
Triple the mass of CaCO3 and show p(CO2) unchanged; then pick the reaction for which Kp = Kc.
Common mistake
Including pure solids in K; Δn as reactants minus products.
In NEET
10 years of papers
Asked 2 times in 10 years of NEET.
See the past questions: Chemical Equilibrium, Equilibrium (chapter)
In JEE Main
42 shifts analysed
52 questions from Equilibrium across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT § "Homogeneous Equilibria"; § "Heterogeneous Equilibria"
- In a homogeneous equilibrium all species are in the same phase, such as all gases or all in one solution.
- For gases, partial pressures can replace concentrations, giving Kp; the two are linked by Kp = Kc(RT)^Δn.
- Δn = (moles of gaseous products) − (moles of gaseous reactants) from the balanced equation.
- When pressure is in bar and concentration in mol L⁻¹, R = 0.0831 bar L mol⁻¹ K⁻¹.
- If Δn = 0 (e.g. H₂ + I₂ ⇌ 2HI), Kp = Kc; for PCl₅(g) ⇌ PCl₃(g) + Cl₂(g), Δn = +1 and Kp = Kc(RT).
- In a heterogeneous equilibrium more than one phase is present, such as water in equilibrium with its vapour or CaCO₃(s) ⇌ CaO(s) + CO₂(g).
- The concentrations of pure solids and pure liquids are constant and are left out of the K expression; for the decomposition of CaCO₃, Kp = p(CO₂).
- Even though pure solids and liquids do not appear in K, they must be present for the heterogeneous equilibrium to exist.
Questions
5 answers
- What does the "Heating limestone in a closed vessel" simulation show?
- CaCO3 heated in a closed vessel: the CO2 pressure settles to Kp whatever the amount of solid, and only temperature moves it; a side panel computes Kp/Kc = (RT)^Δn for chosen reactions.
- What mistake does the "Heating limestone in a closed vessel" simulation fix?
- A common mistake it clears up: including pure solids in K; Δn as reactants minus products.
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 2 times in 10 years of papers.
- Does JEE Main ask questions from Equilibrium?
- Yes. JEE Main asked 52 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Homogeneous and heterogeneous equilibria; Kp" in Equilibrium (Class 11 Chemistry).
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