Lesson 1 of 10 · 7 min
Coordinate geometry recap
NCERT §9.1
Riya is drawing a plan of an imaginary town on graph paper for a project. The town hall sits at the origin, a well at W(4, −1), and a straight canal runs across the sheet. Before she can say anything about the canal, she needs the tools that measure points. Which ones?
The lesson in notes
In short
Coordinate geometry studies figures through algebra: each point of the plane is a pair (x, y), and a curve becomes an equation. René Descartes set out this method in his book La Géométrie of 1637.
The point (6, −4) lies 6 units from the y-axis on the positive x side and 4 units below the x-axis. The point (3, 0) sits on the x-axis itself.
Distance formula: PQ = √((x₂ − x₁)² + (y₂ − y₁)²). From (6, −4) to (3, 0) it is √(9 + 16) = 5.
Section formula: the point dividing the join of (x₁, y₁) and (x₂, y₂) internally in the ratio m : n is ((mx₂ + nx₁)/(m + n), (my₂ + ny₁)/(m + n)). For A(1, −3) and B(−3, 9) in the ratio 1 : 3 it is the origin (0, 0). With m = n it gives the mid-point, here (−1, 3).
Area of the triangle with vertices (x₁, y₁), (x₂, y₂), (x₃, y₃) is ½|x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂)|. For (4, 4), (3, −2) and (−3, 16) it is ½|−72 + 36 − 18| = 27.
If that area comes out zero, the three points lie on one line; they are collinear. The points (1, 1), (2, 3) and (4, 7) give area 0.