Thermal Properties of Matter

Physics · Class 11

Simulation · Physics · Class 11

Two rods in series: finding the junction temperature

"Two rods in series: finding the junction temperature" is a free, interactive Class 11 Physics simulation for NEET and JEE, built on the lesson "Conduction" in Thermal Properties of Matter. The free end of the steel is held at 300 °C and the other end at 0 °C, and the sides are insulated. Change the length of the steel and the second metal; watch where the junction temperature settles. In steady state the same heat current H = KAΔT/L crosses every rod in series, so the poorer conductor takes the larger share of the temperature drop. Set the currents equal and solve for the junction temperature. JEE Main asked 21 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).

From the lesson Conduction in Thermal Properties of Matter. Change the values and watch what happens.

Two rods in series: finding the junction temperaturePhysics · Class 11

In JEE Main

42 shifts analysed

21 questions from Thermal Properties of Matter across the 42 JEE Main shifts Lumi has analysed (2017–2026).

See the past questions

The idea behind it

NCERT §10.9, §10.9.1

  • Heat moves in three ways: conduction, convection and radiation. Conduction passes heat between neighbouring parts of a body through molecular collisions, with no flow of matter; it is the usual way heat moves in solids.
  • A bar of length L and cross-section A with its ends held at T_C and T_D (T_C > T_D) reaches a steady state in which the temperature falls uniformly along it. The heat current is then H = KA(T_C − T_D)/L.
  • K is the thermal conductivity, in W m⁻¹ K⁻¹ (J s⁻¹ m⁻¹ K⁻¹). A large K means a good conductor.
  • K in W m⁻¹ K⁻¹. Metals, lowest first: mercury 8.3, lead 34.7, steel 50.2, brass 109, aluminium 205, copper 385, silver 406. Non-metals: felt and glass wool 0.04, wood 0.12, insulating brick 0.15, body fat 0.20, concrete, glass and water 0.8, ice 1.6. Gases: argon 0.016, air 0.024, hydrogen 0.14.
  • Everyday uses: some cooking pots have copper-coated bottoms to spread heat evenly; plastic foam insulates because it traps pockets of air; a concrete roof gets very hot in summer, so a layer of earth or foam insulation keeps rooms cooler. In nuclear reactors elaborate heat-transfer systems carry away the heat that fission produces.
  • Worked example: a steel rod 15.0 cm long (K = 50.2) and a copper rod 10.0 cm long (K = 385) are joined end to end, sides insulated, the steel end at 300 °C and the copper end at 0 °C; the steel rod has twice the copper's cross-section. In steady state the same heat current crosses both, which gives the junction temperature T = 44.4 °C.
  • Working: 50.2 × 2A × (300 − T)/0.15 = 385 × A × (T − 0)/0.10, i.e. 669.3(300 − T) = 3850 T, so T = 200800/4519.3 ≈ 44.4 °C.
  • Worked example: an iron rod (K = 79) and a brass rod (K = 109), each 0.1 m long and 0.02 m² in area, are joined end to end with the free ends at 373 K and 273 K. The junction settles at T₀ = (K₁T₁ + K₂T₂)/(K₁ + K₂) = 315 K.
  • The pair behaves like a single rod of double length with K′ = 2K₁K₂/(K₁ + K₂) = 91.6 W m⁻¹ K⁻¹, and the heat current through it is H = 916.1 W.

Questions

3 answers

What does the "Two rods in series: finding the junction temperature" simulation show?
The free end of the steel is held at 300 °C and the other end at 0 °C, and the sides are insulated. Change the length of the steel and the second metal; watch where the junction temperature settles.
Does JEE Main ask questions from Thermal Properties of Matter?
Yes. JEE Main asked 21 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
Is this simulation free?
Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Conduction" in Thermal Properties of Matter (Class 11 Physics).

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