Ice in warm water: does it all melt?
"Ice in warm water: does it all melt?" is a free, interactive Class 11 Physics simulation for NEET and JEE, built on the NCERT section "Calorimetry" in Thermal Properties of Matter. Drop ice into warm water: an energy ledger checks whether the water can melt all the ice; final state is either water above 0 °C or an ice-water mix at 0 °C. NEET has asked about this idea 1 time in 10 years of papers. JEE Main asked 21 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
From the lesson Calorimetry in Thermal Properties of Matter. Change the values and watch what happens.
What it shows
NCERT §10.7, §10.8
Drop ice into warm water: an energy ledger checks whether the water can melt all the ice; final state is either water above 0 °C or an ice-water mix at 0 °C.
Controls
3 to try
- Sliderice mass 10–500 g at −20…0 °C
- Sliderwater mass 100–1000 g at 0–90 °C
- Toggleinclude calorimeter (copper, 100 g)
Try this
Find the largest ice mass that 300 g of water at 50 °C can melt completely (≈188 g at 0 °C ice).
Common mistake
Assuming all the ice melts and solving for a negative final temperature.
In NEET
10 years of papers
Asked 1 time in 10 years of NEET.
See the past questions: Calorimetry, Thermal Properties of Matter (chapter)
In JEE Main
42 shifts analysed
21 questions from Thermal Properties of Matter across the 42 JEE Main shifts Lumi has analysed (2017–2026).
The idea behind it
NCERT §10.7
- A system is isolated when it exchanges no heat with its surroundings. When bodies at different temperatures are placed in contact inside such a system, heat flows from the hot ones to the cold ones until they share one temperature.
- Principle of calorimetry: in an isolated system, heat lost by the hot bodies = heat gained by the cold bodies.
- A calorimeter is the device for measuring heat. It is a metal vessel with a stirrer of the same metal, usually copper or aluminium, placed inside a wooden jacket with glass wool between them to keep heat from escaping.
- A thermometer passes through the lid into the liquid. The metal vessel itself takes part in the heat exchange, so its heat must be counted as well as the liquid's.
- Heat changes are found from Q = m s ΔT for each body. For mixtures the unknown is usually a specific heat or the final temperature.
- Worked example: an aluminium sphere of 0.047 kg at 100 °C is dropped into a copper calorimeter of 0.14 kg holding 0.25 kg of water at 20 °C; the final temperature is 23 °C.
- Heat gained by water and calorimeter = (0.25 × 4.18 × 10³ + 0.14 × 0.386 × 10³) × 3 = 3297.1 J. Heat lost by the sphere = 0.047 × s_Al × 77. Equating gives s_Al ≈ 911 J kg⁻¹ K⁻¹ = 0.911 kJ kg⁻¹ K⁻¹.
- Losses to the surroundings make a real measurement less exact, which is why the insulation, lid and quick readings matter.
Questions
5 answers
- What does the "Ice in warm water: does it all melt?" simulation show?
- Drop ice into warm water: an energy ledger checks whether the water can melt all the ice; final state is either water above 0 °C or an ice-water mix at 0 °C.
- What mistake does the "Ice in warm water: does it all melt?" simulation fix?
- A common mistake it clears up: assuming all the ice melts and solving for a negative final temperature.
- Has NEET asked about this idea?
- Yes. NEET has asked about this idea 1 time in 10 years of papers.
- Does JEE Main ask questions from Thermal Properties of Matter?
- Yes. JEE Main asked 21 questions from this chapter across the 42 shifts Lumi has analysed (2017–2026).
- Is this simulation free?
- Yes. It is free and runs in the browser on a phone or a laptop. It belongs to the lesson "Calorimetry" in Thermal Properties of Matter (Class 11 Physics).
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